4n^2+10n-36=0

Solution for 4n^2+10n-36=0 equation:

4n^2+10n-36=0

a = 4; b = 10; c = -36;
Δ = b2-4ac
Δ = 102-4·4·(-36)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*4}=\frac{-36}{8}
=-4+1/2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*4}=\frac{16}{8}
=2
$